2/(x-2)-4/x^2=0

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Solution for 2/(x-2)-4/x^2=0 equation: 


D( x )

x-2 = 0

x^2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:2) U (2:+oo)

2/(x-2)-(4/(x^2)) = 0

2/(x-2)-4*x^-2 = 0

2/(x-2)-4/(x^2) = 0

(2*x^2)/(x^2*(x-2))+(-4*(x-2))/(x^2*(x-2)) = 0

2*x^2-4*(x-2) = 0

2*x^2-4*x+8 = 0

2*x^2-4*x+8 = 0

2*(x^2-2*x+4) = 0

x^2-2*x+4 = 0

DELTA = (-2)^2-(1*4*4)

DELTA = -12

DELTA < 0

2 = 0

2/(x^2*(x-2)) = 0

2/(x^2*(x-2)) = 0 // * x^2*(x-2)

2 = 0

x belongs to the empty set

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